If α, β are the zeros of the polynomial f(x) = ax2 + bx + c, then 
=
Given
f(x) = ax2 + bx + c
α, β are the Zeros
α + β = – b/a
αβ = c/a
1/ α + 1/β = 
1/α2 + 1/β2 = (1/α + 1/β)2 – 2/αβ
= ( – b/c)2 – 2a/c
= 
20
If α, β are the zeros of the polynomial f(x) = ax2 + bx + c, then =
Given
f(x) = ax2 + bx + c
α, β are the Zeros
α + β = – b/a
αβ = c/a
1/ α + 1/β =
1/α2 + 1/β2 = (1/α + 1/β)2 – 2/αβ
= ( – b/c)2 – 2a/c
=