Write 5th term from the end of the A.P. 3, 5, 7, 9, ...., 201.
Here a = 201, a2 = 5, a3 = 7
d = a3 – a2 = a2 – a1
= 7 – 5 = 5 – 3 = 2
tn = a + (n –1)d
tn = 3 + (n–1)2 = 201
(n –1) 2 = 201 – 3 = 198
n – 1 = = 99
n= 99 + 1 =100
5th term from end = 96th term
T95 = 3 + (96 –1)2
T95 = 3 + 95 x 2
T95 = 3 + 190 = 193