Write 5th term from the end of the A.P. 3, 5, 7, 9, ...., 201.

Here a = 201, a2 = 5, a3 = 7

d = a3 – a2 = a2 – a1


= 7 – 5 = 5 – 3 = 2


tn = a + (n –1)d


tn = 3 + (n–1)2 = 201


(n –1) 2 = 201 – 3 = 198


n – 1 = = 99


n= 99 + 1 =100


5th term from end = 96th term


T95 = 3 + (96 –1)2


T95 = 3 + 95 x 2


T95 = 3 + 190 = 193


5