If Sr denotes the sum of the first r terms of an A.P. Then, S3n: (S2n — Sn) is

S2n = (2a + (2n–1) d)


Sn = (2a + (n–1)d)


S3n = (2a + (n–1)d)


S2n –Sn = (2a + (2n–1) d) – (2a + (n–1)d)


= (2a + (n –1) d)


S3n: (S2n — Sn) = (2a + (n–1)d) : (2a + (n –1) d)


= 3

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