From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person cannot hold more than one position?
Total no. of people in committee = 8
No. of positions to be filled = 2
⇒ No. of permutations = 
10
From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person cannot hold more than one position?
Total no. of people in committee = 8
No. of positions to be filled = 2
⇒ No. of permutations =