Given: 5 boys and 4 girls

We can select 3 boys from 5 boys in ⁵C₃ ways

Similarly, we can select 3 boys from 54 girls in ⁴C₃ ways

∴ No. of ways a team of 3 boys and 3 girls can be selected is ⁵C₃ × ⁴C₃

⇒ ⁵C₃ × ⁴C₃ =

⇒ ⁵C₃ × ⁴C₃ =

∴ No. of ways a team of 3 boys and 3 girls can be selected is ⁵C₃ × ⁴C₃ = 40 ways