How many 6-digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10 and no digit is repeated?

The number is divisible by 10 if the unit place has 0 in it.

The 6-digit number is to be formed out of which unit place is fixed as 0


The remaining 5 places can be filled by 1, 3, 5, 7 and 9


Here n = 5


And the numbers of choice available are 5


so, the total ways in which the rest the places can be filled are 5P5



6