For some constants a and b, find the derivative of

Let f(x) =


⇒ f(x) = a2x4 + 2abx2 + b2


So,


⇒


Since,


f’(x) = a2 × 4x3 + 2ab × 2x + 0


= 4a2x3 + 4abx


∴ f’(x) = 4ax (ax2 + b)


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