Minimise Z = – 3x + 4 y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0.
It is given in the question that,
Z = - 3x + 4y
We have to subject on the following equation:
x +2y ≤ 8, 3x+2y ≤ 12, x ≥ 0, y ≤ 0
3x+2y ≤ 12
(x, y) = (0, 6), (4, 0)
x+2y ≤ 8
(x, y) = (0, 4), (8, 0)
We can clearly see that Z is minimum at (4, 0). Hence, minimum value of Z will be - 12