Maximise Z = 5x + 3y subject to 3x + 5y ≤ 15, 5x + 2y ≤ 10, x ≥ 0, y ≥ 0.
It is given in the question that,
Z = 5x + 3y
We have to subject on the following equation:
3x +5y ≤ 15, 5x+2y ≤ 10, x ≥ 0, y ≤ 0
5x+2y ≤ 10
(x, y) = (0, 5), (2, 0)
(x, y) = (0, 3), (5, 0)
We can clearly see that Z is maximum at . Hence, maximum value of Z will be