Maximise Z = 5x + 3y subject to 3x + 5y ≤ 15, 5x + 2y ≤ 10, x ≥ 0, y ≥ 0.

It is given in the question that,

Z = 5x + 3y

We have to subject on the following equation:

3x +5y ≤ 15, 5x+2y ≤ 10, x ≥ 0, y ≤ 0

5x+2y ≤ 10

(x, y) = (0, 5), (2, 0)

(x, y) = (0, 3), (5, 0)

We can clearly see that Z is maximum at . Hence, maximum value of Z will be

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