Without using the Pythagoras theorem, show that the points (4, 4), (3, 5) and (–1, –1) are the vertices of a right-angled triangle.
The vertices of the given triangle are (4, 4), (3, 5) and (–1, –1).
The slope (m) of the line non-vertical line passing through the point (x1, y1) and
(x2, y2) is given by
∴ the slope of the line AB (m1) =
the slope of the line BC (m2) =
the slope of the line CA (m3) =
Now, m1 m3 = -1
⇒ Lines AB and CA are perpendicular to each other
∴ given triangle is right-angled at A (4, 4)
And the vertices of the right-angled ∆ are (4, 4) , (3, 5) and (-1, -1)