Find equation of the line perpendicular to the line x – 7y + 5 = 0 and having x intercept 3.
Given equation of line is x – 7y + 5 = 0
⇒
Which is of the form y = mx + c, where m is the slope of the given line.
∴ slope of the given line is 1/7
Slope of the line perpendicular to the line having slope m is -1/m
Slope of the line perpendicular to the line having a slope of 1/7 is = -7
Equation of line with slope -7 and x intercept 3 is given by y = m(x – d)
⇒ y = -7 (x – 3)
⇒ y = -7x + 21
⇒ 7x + y = 21