Find the values of k for which the line (k–3) x – (4 – k2) y + k2 –7k + 6 = 0 is
Parallel to the x-axis,
The given equation of the
(k–3) x – (4 – k2) y + 6
If the given line is parallel to the x- axis, then
Slope of the given line = Slope of the x- axis.
The given line can be written as
(4 – k2) = (k–3) x + k2 –7k + 6 = 0
⇒ y = 
which is the form y = mx+c
Thus, Slope of the given line =
Slope of x- axis = 0
Then, 
⇒ k – 3 = 0
⇒ k = 3
Therefore, if the given line is parallel to the x – axis, then the value of k is 3.
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