ABC is an isosceles triangle with AB = AC and BD and CE are its two medians. Show that BD = CE.

Given: ΔABC is an isosceles triangle and AB = AC, BD and CE are two medians.


In ΔABD and ΔACE,


AB = AC (given)


We can write it as:


2 AE = 2 AD (as D and E are mid points)


So, AE = AD


A = A (common)


Hence, ΔABD ΔACE (using SAS)


BD = CE (by CPCT)


Hence proved.


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