ABC is an isosceles triangle with AB = AC and BD and CE are its two medians. Show that BD = CE.
Given: ΔABC is an isosceles triangle and AB = AC, BD and CE are two medians.
In ΔABD and ΔACE,
AB = AC (given)
We can write it as:
2 AE = 2 AD (as D and E are mid points)
So, AE = AD
∠A = ∠A (common)
Hence, ΔABD ≅ ΔACE (using SAS)
⇒ BD = CE (by CPCT)
Hence proved.