In Fig. 10.8, BC is a diameter of the circle and BAO = 60 �. Then ADC is equal to:
Given: ∠BAO = 60°
Since, OA and OB are radius of the circle, therefore OA = OB
⇒ ∠ ABO = ∠BAO = 60° (∵ given that ∠BAO = 60°)
Since angle in the same segment are equal, therefore
∠ABC = ∠ADC (angles in the same segment AC are equal)
∠ABC = ∠ABO = 60°
∴ ∠ADC = 60°