In Fig. 10.8, BC is a diameter of the circle and BAO = 60 �. Then ADC is equal to:

Given: BAO = 60°

Since, OA and OB are radius of the circle, therefore OA = OB


ABO = BAO = 60° ( given that BAO = 60°)


Since angle in the same segment are equal, therefore


ABC = ADC (angles in the same segment AC are equal)


ABC = ABO = 60°


ADC = 60°

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