In Fig.10.15, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. Find the value of ∠ACD + ∠BED.
Given: AOB is the diameter.
Join AE and ACDE is a cyclic quadrilateral.
∴ ∠ACD + ∠AED = 180° (sum of opposite angles of a cyclic quadrilateral is 180°) ………………(1)
As diameter subtend a right angle to the circle, therefore,
∠AEB = 90° ………………(2)
Adding equation (1) and (2), we have:
∠ACD + ∠AED + ∠AEB = 180° + 90°
⇒ ∠ACD + ∠BED = 270°