The area of the isosceles triangle is cm2 if the perimeter is 11 cm and the base is 5 cm.
Given Perimeter = 11cm
And a = 5
As the triangle is isosceles, b = c
Perimeter = 11
⇒ a + b + c = 11
⇒ 5 + b + b = 11
⇒ 5 + 2b = 11
⇒ 2b = 6
⇒ b = 3
So, we have a = 5, b = 3, c = 3
s = (a + b + c)/2
⇒ s = (5 + 3 + 3)/2 = 11/2
Area(Δ) = √s(s-a)(s-b)(s-c)
⇒ Area(Δ) =
⇒ Area(Δ) =
⇒ Area(Δ) = (5√11)/4cm2
Hence, the statement is True.