If the side of a rhombus is 10 cm and one diagonal is 16 cm, the area of the rhombus is 96 cm2
To find the area of rhombus, we divide it into two triangles.
As all the sides of a rhombus are equal, we have for a triangle
a = 10, b = 10, c = 16
s = (a + b + c)/2
⇒ s = (10 + 10 + 16)/2 = 36/2 = 18.
Area(Δ) = √s(s-a)(s-b)(s-c)
⇒ Area(Δ) = √18(18-10)(18-10)(18-16)
⇒ Area(Δ) = √18×8×8×2
⇒ Area(Δ) = 48cm2
As the sides of the other triangle are also same, so their areas will also be equal.
Area(Rhombus) = Area(Δ) + Area(Δ)
⇒ Area(Rhombus) = 48 + 48 = 96cm2
Hence, the statement is True.