The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield and earning of Rs. 2000 per m 2 a year. A company hired one of its walls for 6 months. How much rent did it pay?

Question

Philoid · Accepted Answer

a = 13, b = 14, c = 15

s = (a + b + c)/2

⇒ s = (13 + 14 + 15)/2 = 42/2 = 21.

Area(Δ) = √s(s-a)(s-b)(s-c)

⇒ Area(Δ) = √21(21-13)(21-14)(21-15)

⇒ Area(Δ) = √21×8×7×6

⇒ Area(Δ) = 84m²

Cost of advertisements for a year = Area(Δ) × Cost per m²

⇒ Cost of advertisements for a year = 84×2000 = Rs. 168000

As the company only rented the board for 6 months:

Cost of advertisements for 6 months =

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield and earning of Rs. 2000 per m2 a year. A company hired one of its walls for 6 months. How much rent did it pay?

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield and earning of Rs. 2000 per m² a year. A company hired one of its walls for 6 months. How much rent did it pay?