Steps of Construction:

(i) Draw a line segment AB = 3.6 cm.

(ii) Draw an arc with A as centre and 3.0 cm as radius and draw another arc with B as centre and 4.8 cm as radius to intersect each other at C. Join AC and BC.

Thus, we get the required triangle ABC.

On measuring all the angles, we get

∠A = 93°, ∠B = 38.6° and ∠C = 48.4°

Here, the smallest angle is ∠C.

Draw the angle bisector of ∠C. It intersects at A’.

Hence, A’C = 3.5 cm, A’B = 2.5 cm and BC = 4.8 cm.