(i) –3 is a zero of x – 3

False because zero of x – 3 = 3 ∵ x – 3 = 0 ⇒ x=3

(ii) is a zero of 3x + 1

True because zero of 3x + 1 = – 1/3 ∵ 3x + 1 = 0 ⇒ x = – 1/3

(iii) is a zero of 4 –5y

False because zero of 4 – 5y is 4/5 ∵ 4 – 5y =0 ⇒ – 5y = – 4 ⇒ y = 4/5

(iv) 0 and 2 are the zeroes of t² – 2t

T² – 2t = t(t – 2) = 0 ⇒ t = 0 or 2

Hence the zero of the polynomial are 0 and 2 . the given statement is true.

(v) –3 is a zero of y² + y – 6

y² + y – 6 = 0

⇒ y² + 3x – 2x – 6 = 0

⇒ y (y + 3) – 2(x + 3) = 0

⇒ (y – 2) (y + 3) =0

⇒ y = 2 or – 3

Hence – 3 is one of the zero of the polynomial. The given statement is true.