here we would first find out the zero of g(x)and then put the value of in p(x) and solve it.

If p(a)=Q then p(x) is a multiple of g(x) and p(a) # Q then p(x) is not a multiple of g(x) where ‘a’ is a zero of g(x).

(i) g(x)=x – 2 (given)

then, zero of g(x) is 2

Now, p(2)=(2)³ – 5(2)² + 4(2) – 3

= 8 – 20 + 8 – 3 = – 7 ≠ 0

∴ p(x) is not the multiple of g(x) as the remainder ≠ 0.

(ii) p(x)= 2x³ – 11