6x² + 7x – 3

The product of 1^st and the 3^rd term i.e. 18 can be factorized such that the sum or difference should be equal to the middle term.

Thus, the factors of 18 are 2 and 7

⇒ 6x² + 7x – 3

⇒ 6x² + 9x – 2x – 3

⇒ 3x(2+3) – 1(2x+3)

⇒ (3x – 1) (2x+3) Ans.