2x² – 7x – 15

The product of 1^st and the 3^rd term i.e. 30 can be factorized such that the sum or difference should be equal to the middle term.

Thus, the possible factors of 30 are 3 and 10

⇒ 2x² – 10x + 3x – 15

⇒ 2x(x – 5) +3(x – 5)

⇒ (2x+3) (x – 5)