Factorize the following:

(i) 1−64

(i) Given that: 1 – 64a3 – 12a + 48a2


= (1)3 + (−4a)3 + 3(1)2(−4a) + 3(1)(−4a)2


= (1 + (−4a))3


[∵ a3 + b3 + 3a2b + 3ab2 = (a + b)3]


= (1 – 4a)3



=


= (2p)3 + (15)3 + 3(2p)2(15) + 3(2p) (15)2


= (2p + 15)3


[∵ a3 + b3 + 3a2b + 3ab2 = (a + b) 3]


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