Let Y varies directly as x. if y = 12 when x = 4, then write a linear equation. What is value of Y when x = 5?

Given:


y varies directly with x i.e. y is proportional to x.


y = kx, where k is some real number. ------------- (i)


Given y = 12 at x = 3


Putting x = 3 and y = 12 in eq. (i)


We have,


12 = 3k


k = = 4


Thus the given linear equation is y = 4x


At x = 5: y = 4 x 5 = 20.


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