The following observed value of x and y are thought to satisfy a linear equation. Write the linear equation-


Draw the graph using the value of x, y as given in the above table.


At what points the graph of the linear equation


(i) cuts the X-axis ?


(ii) cuts the Y-axis?


The linear equation for the line will be-


y = mx + c


Where, c is the y-intercept, which from the graph is 2.


⇒ c = 2.


Taking x1 = 6, y1 = – 2 and x2 = – 6, y2 = 6


Now, m = slope of the line






∴ the linear equation will be-



⇒ 3y = – 2x + 6 (multiplying whole equation by 3)


⇒ 2x + 3y – 6 = 0


Now, the point where graph cuts:


(i)x-axis


For this, y = 0.


∴putting x = 0 in 2x + 3y – 6 = 0, we get-


⇒ 2x + 3×0 – 6 = 0


⇒ 2x = 6


⇒ x = 3


∴ the point where graph cuts x-axis is(3, 0).


(ii) y-axis


For this, x = 0.


∴putting x = 0 in 2x + 3y – 6 = 0, we get-


⇒ 2×0 + 3y – 6 = 0


⇒ 3y = 6


⇒ y = 2


∴ The point where graph cuts y-axis is (0, 2).


2