Draw the graph of the linear equation 3x + 4y = 6. At what points, the graph cuts X and Y-axis?
The given equation is 3x + 4y = 6. To draw the graph of this equation, we need at least two points lying on the graph.
Now, the point where graph cuts:
(i) X-axis
For this, y = 0.
∴putting x = 0 in 3x + 4y = 6, we get-
⇒ 3x + 4×0 = 6
⇒ 3x = 6
⇒ x = 2
∴ The point where graph cuts x-axis is (2, 0).
(ii) Y-axis
For this, x = 0.
∴ putting x = 0 in 3x + 4y = 6, we get-
⇒ 3×0 + 4y = 6
⇒ 4y = 6
⇒
∴ the point where graph cuts y-axis is(0, 1.5).
Now plot the points M (0, 1.5) and N (2, 0) and join them to get the straight line, i.e., graph of the equation.