Draw the graph of the linear equation 3x + 4y = 6. At what points, the graph cuts X and Y-axis?

The given equation is 3x + 4y = 6. To draw the graph of this equation, we need at least two points lying on the graph.


Now, the point where graph cuts:


(i) X-axis


For this, y = 0.


putting x = 0 in 3x + 4y = 6, we get-


3x + 4×0 = 6


3x = 6


x = 2


The point where graph cuts x-axis is (2, 0).


(ii) Y-axis


For this, x = 0.


putting x = 0 in 3x + 4y = 6, we get-


3×0 + 4y = 6


4y = 6



the point where graph cuts y-axis is(0, 1.5).


Now plot the points M (0, 1.5) and N (2, 0) and join them to get the straight line, i.e., graph of the equation.



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