Let the force be y, acceleration be x and constant mass be m.

Now, ∵ y α x (Newton’s second law of motion)

⇒ y = mx

Now, given that m = 6kg

⇒ y = 6x is the equation.

To draw the graph of this equation, we need at least three points lying on the graph.

For x = 0, y = 0, therefore, (0, 0) lies on the graph, i.e., graph passes through origin.

For x = 1, y = 6, therefore, (1, 6) lies on the graph.

For y = 1, , therefore, (0.17, 1) lies on the graph.

Now plot the points M (0, 0) and N (1, 6) and O () and join them to get the line and now extend this straight line to get more solutions.

Now, the values of y for given x can be calculated by putting the given values in equation y = 6x.

But it is given to do so by graph.

Now, to get the value of y from graph for given values of x, we’ll draw perpendicular from the point where a lies on the graph to the y-axis to get the value of corresponding y.

Therefore, by doing so, we get-

The force required when the acceleration produced is

(i) 5 ms ^{– 2} is 30N

(ii) 6 ms ^{– 2} is 36N

(where N(Newton) = kgms ^{– 2})