If p and q are in inverse variation, then (p + 2) and (q – 2) are also inverse proportion.
False
If p and q are in inverse proportion, then
xy = k(constant)
e.g. Let p = 3 and q = 4
Then, pq = 3×4 = 12
Now, p + 2 = 3 + 2 = 5 and q-2 = 4-2 = 2
(p + 2) (q-2) = 5×2 = 10 [not in inverse proportion]
Hence, (p + 2) and (q-2) cannot be in inverse proportion.