According to the question;

In one’s column A + 3 = 5

⇒ A is the number whose addition with 3 gives 5 in one’s place

∵ A is a digit hence its value is between 0 and 9

∴ A = 2 (2 + 3 = 5).

In ten’s column 5 + B + 0 = 6 (there is no carry from A + 3)

⇒ 5 + B = 6

⇒ B = 6 – 5 = 1;

Hence A = 2 and B = 1

∴ Option (c) is correct.