Fill in the blanks to make the statements true.
The difference of three-digit number and the number obtained by putting the digits in reverse order is always divisible by 9 and …………… .
Let x, y and z be the digits in a three-digit number A = xyz.
Reversing the digits, we get B = zyx.
Sum of the digits in A is (100x + 10y + z).
Sum of the digits in B is (100z + 10y + x).
Difference S = A + B = (100x + 10y + z) - (100z + 10y + x).
S = 100x-x + 10y-10y + z-100z = 99x-99z
99(x-z) = 9x11(x-z)
The number is divisible by 9 and 11.