True(T)

Here, we have

This implies B + C is either 2 or two digit number whose one’s

digit is 2.

Its given that B ≠ 0, C ≠ 0,so B + C is a two digit number whose one’s digit is 2.

When B = C = 1, then A should be 3 so that we have

But in this case A + B + C ≠ 14,so B = C = 1 cannot happen.

(I)Here either B or C should be 5 or 7 and A should be 3 so that

A + B + C = 14.

(II)If B = C = 6 and A = 2, then

and A + B + C = 14