A) The person started from his home at 10 am, since the distance is 0 km at that time. (Note :Even though the distance at 10 pm is also 0 km, it is after the journey)

B) The first part of the graph stops at the value of 20 on the y-axis after which it first becomes constant and then starts decreasing. Hence, he travelled 20 km in the first hours of his journey.

C) The graph from 3 pm to 5 pm is parallel to the x-axis. This indicates that the person did not travel any distance in those 2 hours. So, the person was at one place from 3 pm to 5 pm.

D) He travels 20 km in the first part of the day and again travels 20 km to come back to his starting point.

∴ Total distance = 20 + 20 = 40 km.

E) The first 8 hours of the journey mean from 10 am to 6 pm. He covered 20 km up to 3 pm.

He was in the same place till 5 pm. So distance covered from 3 pm to 5 pm = 0 km.

The distance at 6 pm is 16 km and at 5 pm is 20 km.

So, distance covered from 5 pm to 6 pm = 20 – 16 = 4 km.

∴ Total distance covered in the first 8 hours = 20 + 4 = 24 km.

F) He covered 16 km of his journey at 2 pm. (Note :Even though the graph shows 16 km at 6 pm, too, the distance covered at 6 pm will be 24 km.)

G)

(a). The total distance travelled from A to B = 20 – 0 = 20 km

Now, we first need to convert 3 pm into 24 hour format.

3 pm = 12 + 3 = 15 pm

The total time taken from A to B = 15 – 10 = 5 hours

∴ Average speed from A to B = = = 4 km/hr.

(b) The total distance travelled from B to C = 0 km (since the distance is constant)

The time taken from B to C = 5 pm – 3 pm = 2 hours.

∴ Average speed from B to C = = = 0 km/hr.

(c) He returned home at 10 pm since the distance becomes 0 again at 10 pm.