Angle Sum Property = ∠A + ∠B + ∠C = 180°[T1]

∠ DAC = 130° and ∠ ABE = 140°

∠ DAC + ∠ DAB = 180° (sum of the angle on a straight line at point is 180°)

∴ ∠DAB = 180° - ∠ DAC

⇒ ∠ DAB = 180° - 130° = 50°

Similarly,

∠ ABE + ∠ ABD = 180° (sum of the angle on a straight line at point is 180°)

∴ ∠ABD = 180° - ∠ ABE

⇒ ∠ DAB = 180° - 140° = 60°

∠ BDB’ = ∠ DAB + ∠ DBA

(if a side of a triangle is produced, the exterior angle so formed, is equal to the sum of the two interior opposite angles)

∠ x° = 50° + 60° = 110°

Hence, option C is correct.