Construct trapezium PQRS with the following measurements. Find also its area.
is parallel to PQ = 6.8 cm, QR = 7.2 cm, PR = 8.4 cm and RS = 8 cm.
Given. PQRS is a trapezium.
PQ = 6.8 cm, RS = 8 cm , QR = 7.2 cm, PR = 8.4 cm
Formula used. Area of trapezium = × height × sum of parallel sides
Area of trapezium = × height × (PQ + SR)
Steps of Construction
Step 1 : Draw a line PQ of 6.8cm
Step 2 : Make an arc of 8.4cm from point P and 7.2cm from point Q
Step 3 : Mark the intersection point as R and join PR and QR
Step 4 : Draw a ray RS’ parallel to PQ from point R
Step 5 : Make arc of 8cm on ray RS’ from point R and name intersection point S
Step 6 : Join point S and P to form trapezium PQRS
Step 7 : Draw a perpendicular on PQ from point R and name the intersection point as E
Area of trapezium = × height × (PQ + SR)
= × RE × (PQ + SR)
= × 6.9cm × (6.8cm + 8cm)
= 51.06cm2
Conclusion. Hence; Trapezium PQRS is constructed and its area is
51.06cm2