Given. ABCD is a parallelogram.

AB = CD ; BC = AD , AB = 7 cm, BC = 5 cm , ∠ABC = 60°

Formula used. Area of parallelogram = base × height

Steps of construction

Step 1 : Draw a line AB of 7cm

Step 2 : Make an angle of 60° on point B and extend ray to BC’

Step 3 : Make an arc of 5cm on ray BC’ from point B and name the

intersection point as C

Step 4 : Draw arc of 5cm and 7cm from point A and C respectively

Step 5 : Mark the intersection point as D and join AD and CD

Step 6 : Draw a perpendicular on AB from point C and name the intersection point as E

Area of parallelogram = base × height

= AB × CE

= 7cm × 4.3cm

= 30.1cm²

Conclusion. Hence; parallelogram ABCD is constructed and its area

is 30.1cm²