Given. ABCD is a parallelogram.

AB = CD ; BC = AD

AB = 8.5 cm, AD = 6.5 cm

∠DAB = 100°

Formula used. Area of parallelogram = base × height

Steps of construction

Step 1 : Draw a line AB of 8.5cm

Step 2 : Make an angle of 100° on point A and extend ray to AD’

Step 3 : Make an arc of 6.5cm on ray AD’ through point A and name the intersection point as D

Step 4 : Draw arc of 6.5cm and 8.5cm from point D and B Respectively

Step 5 : Mark the intersection point as C and join DC and BC

Step 6 : Draw a perpendicular on AB from point C and name the intersection point as E

Area of parallelogram = base × height

= AB × CE

= 8.5cm × 6.4cm

= 54.4cm²

Conclusion. Hence; parallelogram ABCD is constructed and its area

is 54.4cm²