Draw parallelogram ABCD with the following measurements and calculate its area.

AC = 8 cm, BD = 6 cm and COD = 90° where and intersect at ‘O’.

Given. ABCD is a parallelogram.

AC = 8 cm, BD = 6 cm


COD = 90°


Formula used. Area of parallelogram = base × height


Steps of construction


Step 1 : Draw line segment AC of 8cm


Step 2 : Mark O as midpoint of AC



Step 3 : Draw line B’D’ through O which makes COD’ = 120°



Step 4 : Make Arcs of 3cm form O on both sides of B’D’



Step 5 : Join AB;BC;CD;DA



Step 6 : Draw a perpendicular on AB from point D and name the intersection point as E



Area of parallelogram = base × height


= AB × DE


= 5cm × 4.8cm


= 24cm2


Conclusion. Hence; parallelogram ABCD is constructed and its area


is 24cm2


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