For the circuit shown in the diagram below:
What is the value of:
(i) current through 6 Ω resistor?
(ii) potential difference across 12 Ω resistor?
The resistance of 6 ohm and 3 ohm are connected in series. Therefore, their net resistance can be calculated as
R= R1+R2
Here, R1= 6ohm
R2= 3ohm
so R= 6ohm +3ohm= 9 ohm
The current through 6 ohm resistor= current through line 1 = I= V/R =4/9=0.44V
(ii) The resistance of 12ohm and 3 ohm are connected in series. Therefore, their net resistance can be calculated as
R= R1+R2
Here, R1= 12ohm
R2= 3ohm
so R= 12ohm +3ohm= 15 ohm
The current through them = I= V/R =4/15
Potential difference across 12 ohm resistor= 4/15 ×12 =3.2