Two resistors, with resistances 5 Ω and 10 Ω respectively are to be connected to a battery of emf 6 V so as to obtain:
(i) minimum current flowing
(ii) maximum current flowing
(a) How will you connect the resistances in each case?
(b) Calculate the strength of the total current in the circuit in the two cases.
(i) For obtaining minimum current, the two resistors should be connected in parallel.
(ii) For obtaining maximum current, the two resistors should be connected in series.
(a) R1= 5 ohm, R2= 10 ohm and V = 6 V
For parallel combination
R= 10/3 ohm
Total current in the circuit
For series combination
R=R1+R2
R=5+10=15 ohm
Total current in the circuit.
(b) So the current in each case is 1.8 A and 0.4A in parallel and series circuit respectively.
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