A p.d. of 4 V is applied to two resistors of 6 Ω and 2 Ω and 6 Ω connected in parallel. Calculate:

(a) the combined resistance


(b) the current flowing in the main circuit


(c) the current flowing in the 6Ω resistor.

(a) When two resistors are connected in series, their resultant resistance is given by

R= R1+R2


Here R1 = 6 ohm


R2= 2 ohm


Combined resistance, R = R1 + R2 = 6+2 = 8 ohm


(b) We know that the current, I= V/R


Here R = 8 ohm


V= 4V


I = 4/8 = 0.5 amp


(c) Potential difference across 6ohm resistor V= I x R1 = 0.5 x 6 = 3 V


25