In the circuit given below:
(a) What is the combined resistance?
(b) What is the p.d. across the combined resistance?
(c) What is the p.d. across the 3 Ω resistor?
(d) What is the current in the 3Ω resistor?
(e) What is the current in the 6 Ω resistor?
A
The resistors of 6 ohm and 3 ohm are connected in parallel. Therefore, their combined resistance can be calculated as
R= 2 ohms
(b) The p.d. across the combined resistance, V= IR
Here I = 6A and combined resistance = 2 ohms.
So, V= 6 x 2 = 12 V
(c) In parallel connection potential difference remains constant, so Potential difference across 3ohm resistor =12 V
(d) The current in the 3Ω resistor
I= V/R1
I= 12/3 =4A
(e) Current flowing through the 6 ohm resistor = V/R2 = 12/6 = 2 A