Show with the help of diagrams, how you would connect three resistors each of resistance 6 Ω so that the combination has resistance of (i) 9 Ω (ii) 4 Ω
(i)
To obtain 9Ω resistance two resistance are connected in parallel,
Let the resultant resistance for parallel circuit=R
1/R=1/6+1/6
1/R=2/6
R=3
Effective resistance=6+3 = 9ohms
(ii) To obtain 4Ω resistance all resistance are connected in parallel
So the effective resistance will be R for each circuit
Or R= 2 Ω
Total resistance = 2 Ω+2 Ω=4Ω