Show with the help of diagrams, how you would connect three resistors each of resistance 6 Ω so that the combination has resistance of (i) 9 Ω (ii) 4 Ω

(i)


To obtain 9Ω resistance two resistance are connected in parallel,


Let the resultant resistance for parallel circuit=R


1/R=1/6+1/6


1/R=2/6


R=3


Effective resistance=6+3 = 9ohms


(ii) To obtain 4Ω resistance all resistance are connected in parallel



So the effective resistance will be R for each circuit



Or R= 2 Ω


Total resistance = 2 Ω+2 Ω=4Ω


43