How will you connect three resistors of resistance 2Ω, 3 Ω and 6 Ω to obtain a total resistance of: (a) 4Ω, and (b) 1 Ω?

(a) For total Resistance to be 4

we will connect 2 ohm resistance in series with parallel combination of 3 and 6 ohm resistance. When 3 and 6 ohm are in parallel combination then 1/R=1/3+1/6


or R=2


Now this R connected in series with 2 ohm resistance will give equivalent resistance = 2+ 2 = 4 ohm.


For total Resistance to be 1 ohm


All the given resistance should be connected in parallel combination 1/R’= 1/2+1/3+1/6


Or R'=1 ohm


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