What is (a) highest, and (b) lowest, resistance which can be obtained by combining four resistors having the following resistances?

Question

What is (a) highest, and (b) lowest, resistance which can be obtained by combining four resistors having the following resistances? 4&#x3A9;, 8&#x3A9;, 12&#x3A9;, 24&#x3A9;

Philoid · Accepted Answer

(a) To obtain the highest resistance we must connect the given resistances in series.

Highest resistance R = 4 + 8 + 12 + 24 = 48ohms

(b) To obtain the lowest resistance we must connect the given resistances in parallel.

1/R=1/4+1/8+1/12+1/24

On solving we get, R=2ohms

What is (a) highest, and (b) lowest, resistance which can be obtained by combining four resistors having the following resistances?4Ω, 8Ω, 12Ω, 24Ω

What is (a) highest, and (b) lowest, resistance which can be obtained by combining four resistors having the following resistances?
4Ω, 8Ω, 12Ω, 24Ω