In figure below, O is the center of the circle and A, B are point on the circle.
Compute ∠A and ∠B.
In Δ OAB,
OA = OB = r = Radius of circle
In a triangle with 2 equal sides, the angles opposite to equal sides are equal.
∴ ∠OAB(∠A) = ∠OBA(∠B) = y° …(eq)1
In a triangle,
Sum of all angles of a triangle is 180°
∴ In Δ OAB,
∠O + ∠A + ∠B = 180°
∴ 60 + y + y = 180°
∴ 60 + 2y = 180°
∴ 2y = 180-60
= 120
∴
∴ ∠A = ∠B = 60° (from eq1)