Draw a quadrilateral and mark any two outer angles. Is there any relation between the sum of these two and the inner angles at the outer two and the inner angles at the other two vertices?
∠ ADC + ∠ CDF = 180° (linear pair of angles at a vertex)
∠ CDF = 180° - ∠ ADC …(1)
∠ ABC + ∠ CBE = 180° (linear pair of angles at a vertex)
∠ CBE = 180° - ∠ ABC … (2)
Sum of two exterior angles marked.
⇒ ∠ CBE + ∠ CDF = 180° - ∠ ABC + 180° - ∠ ADC
⇒ ∠ CBE + ∠ CDF = 360° - (∠ ABC + ∠ ADC) …(3)
In ABCD
∠ ABC + ∠ BCD + ∠ ADC + ∠ DAB = 360°
[sum of all interior angles 4-sided polygon is 360°]
⇒ ∠ ABC + ∠ ADC = 360° - ∠ BCD - ∠ DAB
Put this value in equation (3)
⇒ ∠ CBE + ∠ CDF = 360° - (360° - ∠ BCD - ∠ DAB)
⇒ ∠ CBE + ∠ CDF = 360° - 360° + ∠ BCD + ∠ DAB
⇒ ∠ CBE + ∠ CDF = ∠ BCD + ∠ DAB
Hence, yes there is a relation between the sum of exterior angles marked and sum of inner angles at the other two vertices.