In Fig. 6.15 all triangles are equilateraland AB = 8 units. Other triangles have been formed by taking the mid points of the sides. What is the perimeter of the figure?
Given other triangles are formed by taking midpoints
DF = FE = DE / 2
= 4 / 2
= 2 units
In Δ DIF
DI = DF = IF = 2 units
In Δ TKN and Δ RQU
TK = KN = TN = RQ = UQ = UR = 2 units
NC = RP = 2 units
IG = GF = 1 unit
In Δ HIG
HG = HI = GI = 1 unit
In Δ MLK and Δ XQS
ML = MK = LK = SQ = XS = QX = 1 unit
LN = XR = 1 unit
Perimeter = 4 + 2 + 1 + 1 + 1 + 2 + 4 + 4 + 2 +1 + 1 + 1 + 2 + 4 + 4 + 2 + 1 + 1 + 1 + 2 + 4
= 45 cm
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