Given x + 1 = 0 ⇒ (a)

2x + 2 = 0 ⇒ (b)

In the second equation we are going to take 2 as common since all the term in it is multiple of 2

2(x + 1) = 0

Sending 2 to R.H.S

X + 1 =

X + 1 = 0 ⇒ (c)

We can see that equation a & c are same

So, they will have same solutions.

So, given statement is True