Write two equations for which 2 is the solution.
Let the two number be x and y, which has solution 2 in equation
1. For getting first equation, the number x is multiplied by 2, then the number is 2x
After that, 3 is subtracted from it which results into 1
Hence, 2x – 3 = 1
⇒ 2x = 3+1
⇒ 2x = 4
⇒x = 2
2. For getting second equation, the number y is multiplied by 3, then the number is 3y
After that, it will be added to 4 which results into 10
Hence, 3y + 4 = 10
⇒ 3y = 10-4
⇒ 3y = 6
⇒y = 2
Hence, required equation are 2x - 3 = 1 and 3y + 4 = 10